How many grams of oxygen are required to burn completely 570 grams of octane?
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2C8H18 + 25O2 =16CO2 + 18H2O
HENCE,it can be concluded that
25 gm of oxygen is required for 2gm of octane
Therefore
It would take 7125 gm of oxygen to burn 570gm of octane (by unitary method)
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