Question

How many grams of oxygen can be prepared by the decomposition of 12 grams of mercurydiaoxide?

Answer 1

Answer:

3 mole

Explanation:

Answer 2

Concept:

• Decomposition of Mercury dioxide HgO
• Mole concept

Given:

• Amount of mercuric oxide HgO = 12 g
• The reaction is 2HgO --> 2Hg +O₂

Find:

• The amount of oxygen that can be prepared from the decomposition of 12 g of mercuric oxide

Solution:

The reaction of decomposition of mercuric oxide is

2HgO --> 2Hg +O₂

2 moles of mercuric oxide form 1 mole of oxygen.

1 mole of mercuric oxide forms 0.5 moles of oxygen.

number of moles of mercuric oxide = weight/molar mass

molar mass of mercuric oxide = 216.6 g

number of moles of mercuric oxide = 12/216.6 = 0.0554

the number of moles of oxygen = 0.0554/2 = 0.0277

Mass of oxygen = 0.0277 * 16 = 0.443 g

The amount of oxygen that can be prepared is 0.443g.

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