how many grams of oxygen gas contain the same number of molecules as 16 gramsvof sulphur dioxide gas? O =16 u, S=32 u
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0
Answer:
8 grams of oxygen will contain the same number of molecules as 16 grams of sulphur dioxide.
Explanation:
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Answered by
0
Explanation:
Moles of SO
2
=
64
16
=0.25
Given, Moles of SO
2
=Moles of O
2
Hence, 0.25=
32
m
O
2
⇒m
O
2
=0.25×32=8 g
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