Question

how many grams of Oxygen gas contains the same number of molecules of as 16 gram of Sulphur dioxide gas???

Answer 1

We know that equal moles of all gases contain equal number of molecules.
1 mole of sulphur = 32 + 2 * 16 = 64 gm
16 gram of sulphur = 1/64 * 16 = 1/4 mole

1/4 mole of sulphur dioxide will have the same number of molecules as 1/4 moles of oxygen.
1 mole of oxygen = 32 gm
1/4 mole of oxygen = 1/4 * 33 = 8 gm

Therefore, 8 gm of oxygen gas contains the same number of molecules as 16 gm of sulphur dioxide gas.

Hope you like it....
Mark as brainliest....

Answer 2

Answer:1 mole of Co2=c+o2

=12+32

=44g

44g of Co2=1mole

16g of Co2=1/44×16mole

1mole of O2=2×16=32g

1/2.75mole of O2

=100/2.75×32=128/11

=11.63

=11.63g of O2

Hope it helps you ☺️ ☺️

Plzzz Mark as brainlist

Thank you

Explanation: