Chemistry, asked by ambicagovind2, 11 months ago

How many grams of oxygen is required for complete combustion of 29g of butane as per the equation C4H10+ 4.5O2=2CO2+5H2O


priyankasubhadarsini: 72 grams

Answers

Answered by priyankasubhadarsini
0

72g of butane is required for 29 grams of butane.

Attachments:

ambicagovind2: Your answer is not in the options, Thanks for the effort anyway
priyankasubhadarsini: What are the options?
priyankasubhadarsini: Can u plzz help me out with this
Answered by poodarvitan
0

72 gm of butane is required

Similar questions