Question

how many grams of oxygen required for 27 gram of aluminium​

Answer 1

Answer:

Explanation:

Answer:

The balanced equation for the given reaction is:

4 Al           +          3 O2    -------->           2 Al2O3

Atomic mass of Al = 27g

Atomic mass of O2 = 2 � 16 = 32g

Mole ratio of aluminium and oxygen can be given as:

Al    :  O2

4     :   3

1    :  3/4

Mass of O2 required = 3/4 � 32 =24g

Answer 2

Answer:

24 gram of oxygen is required for 27 gram of aluminium.