How many grams of oxygen will be required to react completely with 27g of Al (Al=27, O= 16 )
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1
Answer:
48 grams
Answer. Explanation: According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles. Thus 48 grams of oxygen will be required to react completely with 27 gram of Al.
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Answer:
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Explanation:
ANSWER----------∴। ∴27g of Al reacts will oxygen=3×324×27×27=24g.
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