Question

How many grams of oxygen will be required to react completely with 27g of Al (Al=27, O= 16 )​

Answer 1

Answer:

48 grams

Answer. Explanation: According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles. Thus 48 grams of oxygen will be required to react completely with 27 gram of Al.

Answer 2

Answer:

PLEASE MARK ME BRAIN LIST

Explanation:

ANSWER----------∴। ∴27g of Al reacts will oxygen=3×324×27×27=24g.

have great day ahead ☺️