How many grams of oxygen will be required to react completely with 27 g of Al? (Atomic mass : Al = 27, O = 16)
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According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles. Thus 48 grams of oxygen will be required to react completely with 27 gram of Al.
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