Question

How many grams of oxygen will react with 20.0g of hydrogen to form water?

Answer 1

Answer:

The gram change in kilograms

20.0/1000

=0.02kilo

Answer 2

Answer:

20.0 grams

Explanation:

To find out how many grams of oxygen will react with 20.0 grams of hydrogen to form water (H2O), we need to apply the stoichiometry of the chemical reaction between hydrogen and oxygen to form water.

The balanced chemical equation for the reaction is:

2H2 + O2 -> 2H2O

From the balanced equation, we can see that 2 moles of hydrogen (H2) react with 1 mole of oxygen (O2) to produce 2 moles of water (H2O).

Step 1: Calculate the number of moles of hydrogen.

Given mass of hydrogen = 20.0 grams

Molar mass of hydrogen (H2) = 2.016 grams/mole

Number of moles of hydrogen = Mass / Molar mass

Number of moles of hydrogen = 20.0 grams / 2.016 grams/mole ≈ 9.92 moles

Step 2: Use stoichiometry to find the number of moles of oxygen.

From the balanced chemical equation, we see that 2 moles of hydrogen react with 1 mole of oxygen. So:

Number of moles of oxygen = (Number of moles of hydrogen) / 2

Number of moles of oxygen = 9.92 moles / 2 ≈ 4.96 moles

Step 3: Calculate the mass of oxygen.

Given that the molar mass of oxygen (O2) is approximately 32.00 grams/mole.

Mass of oxygen = Number of moles of oxygen × Molar mass of oxygen

Mass of oxygen = 4.96 moles × 32.00 grams/mole ≈ 158.72 grams

So, approximately 158.72 grams of oxygen will react with 20.0 grams of hydrogen to form water.