Chemistry, asked by cvrohit, 1 year ago

How many grams of phosphoric acid is required to completely neutralise 120 gm of sodium hydroxide. The products are sodium phosphate and water

Answers

Answered by prmkulk1978

Chemical Equation:
H3PO4 + 3NaOH --->Na3PO4 + 3H2O
Here molecular mass of H3PO4 is 98u
NaOH molecular mass is 40u
Na3PO4 MOLECULAR mass is 164u and water MOLECULAR mass is 18u
So we get,
H3PO4+3NaOH ---->Na3PO4 + 3H2O
98g 120g 164g 54g
Therefore 98g of H3PO4 is required to completely neutralise 120g of NaOH.

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