Question

How many grams of phosphorous needs to react with 35.5 l of o2 at 1atm and 273 k?

Answer 1

moles O2 = 35.5 / 22.4 =1.58

the ratio between P4 and O2 is 1 : 5

moles P4 required = 1.58/5=0.316

molar mass P4 = 4 x 30.9738 g/mol=123.895 g/mol

mass P4 = 0.316 mol x 123.895 g/mol=39.2 g