Question

How many grams of potassium are present in 12.80 g of K4SiO4?

Answer 1

let 'x g' of K are present in 12.80 g of K4SiO4

x/76=12.80/379.36

x=12.80*76/379.36=2.56 g

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Answer 2

Answer:

pta ni

Explanation:

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