Geography, asked by kaurtania1033, 8 months ago

How many grams of pure sulphuric acid is present in 0.05 mole of it?

Answers

Answered by vermaanya0106

2

Explanation:

molarity= w/m*1000/l

=> w= Molarity x l/1000 x m

=> w= 0.5 x 0.05 x 98

w= 2.45g

Answered by aadilkhan7

4

Hiii

Your answer is

2.45g

Hope it will help you

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