How many grams of silver will be displaced from a solution of agno3 by 4 grams of magnesium
Answers
This is just example
How many grams of silver will be obtained when an aqueous silver nitrate solution is electrolyzed for 20 minutes with a constant current of 2.4 Amp?
Answer
The first thing you need to do is write an equation for the reduction (or oxidation- it doesn’t matter in this case) of silver:
Ag->Ag+ + e-
When 1 mole of silver metal is oxidized, it produces 1 mole of silver ion and 1 mole of electrons.
Now, for the actual calculations. In chemistry class, I assume that you learned that 1 Faraday=96500 Coulombs=96500 Amp seconds=1 mole of electrons. You should notice which conversion you’ll be using.
Use unit analysis and mole ratios to calculate your answer:
2.4 Amp * 20 min * (60 s/1 min) * (1 mol e-/96500 Amp•s) * (1 mol Ag/1 mol e-) * (107.87 g Ag/1 mol Ag) = 3.2 g Ag
Your answer is 3.2 grams of silver.
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Answer:
Weight of magnesium = 4 g
We know that, Weight of silver displaced (M)/Weight of magnesium = Equivalent weight of silver/ Equivalent weight of magnesium or
M/4 = 108/12 or M = 108 x 4 /12 = 36
Explanation: