Question

How many grams of so3 are produced from 1 mole s8

Answer 1

3 moles O2 reacts to give 2 moles SO3 Si 1 mole O2 reacts to give 2/3 moles SO3 So 0.03125 moles O2 reacts to give (2/3 x 0.03125) moles SO3 = 0.02083 moles SO3 mass = molar mass x moles = 80.06 g/mol x 0.02083 moles 1.668 g = 1.7 g (2 sig figs)

Answer 2

Answer : The mass of SO_3SO

3

produced are, 640 grams.

Solution : Given,

Moles of S_8S

8

= 1 mole

Molar mass of SO_3SO

3

= 80 g/mole

The balanced chemical reaction will be,

S_8+12O_2\rightarrow 8SO_3S

8

+12O

2

→8SO

3

From the balanced reaction, we conclude that

1 mole of S_8S

8

react to give 8 moles of SO_3SO

3

Now we have to calculate the mass of SO_3SO

3

\text{Mass of }SO_3=\text{Moles of }SO_3\times \text{Molar mass of }SO_3Mass of SO

3

=Moles of SO

3

×Molar mass of SO

3

\text{Mass of }SO_3=(8mole)\times (80g/mole)=640gMass of SO

3

=(8mole)×(80g/mole)=640g

Therefore, the mass of SO_3SO

3

produced are, 640 grams.