how many grams of so3 are produced from 1 moles of S8
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(1) S8 + 8O2 = 8SO2
(2) 2SO2 +O2 = 2SO3
If we multiply (2) by 4,
We get 8SO2 + 4O2 = 8SO3 —(3)
Adding (1)+(3)
S8 + 8SO2 + 8O2 = 8SO2+ 8SO3
Cancelling 8SO2 from both side of the reaction, S8 + 8O2 = 8SO3
We can see that from 1 mole of S8, 8 moles of SO3 are formed. From x moles of S8, 8x moles of SO3 are formed.
Here x=1 , therefore 8 moles of SO3 will be formed.
No. of grams = moles × molecular weight
No. of grams = 8 × 80
No. of grams = 640gm
(2) 2SO2 +O2 = 2SO3
If we multiply (2) by 4,
We get 8SO2 + 4O2 = 8SO3 —(3)
Adding (1)+(3)
S8 + 8SO2 + 8O2 = 8SO2+ 8SO3
Cancelling 8SO2 from both side of the reaction, S8 + 8O2 = 8SO3
We can see that from 1 mole of S8, 8 moles of SO3 are formed. From x moles of S8, 8x moles of SO3 are formed.
Here x=1 , therefore 8 moles of SO3 will be formed.
No. of grams = moles × molecular weight
No. of grams = 8 × 80
No. of grams = 640gm
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