Question

how many grams of so3 are produced from 1 moles of S8

Answer 1

(1) S8 + 8O2 = 8SO2

(2) 2SO2 +O2 = 2SO3

If we multiply (2) by 4,

We get 8SO2 + 4O2 = 8SO3 —(3)

Adding (1)+(3)

S8 + 8SO2 + 8O2 = 8SO2+ 8SO3

Cancelling 8SO2 from both side of the reaction, S8 + 8O2 = 8SO3

We can see that from 1 mole of S8, 8 moles of SO3 are formed. From x moles of S8, 8x moles of SO3 are formed.

Here x=1 , therefore 8 moles of SO3 will be formed.

No. of grams = moles × molecular weight

No. of grams = 8 × 80

No. of grams = 640gm