Question

How many grams of so3 are produced when 20.0g fes2?

Answer 1

Answer:i remember these ok the key is to turn FeS2 into moles then use the balanced equation to see how many moles of SO3 is produced and use O2 to see many many moles of SO3 you produce. FeS2 or O2 one of them is going ot be your limiting reactant so you wll use that for expressing SO3 mounts. SO

20grams FeS2 ( 1 mol of FeS2/119.65g) ( 8mol SO3/ 2 mol FeSo3) =.668mol SO3

16 g of O2 ( 1mol O2/ 32g )(8 mol SO3/ 15mol O2) =0.267 mol SO3

we see that O2 is our limiting reactant so we must use O2 to see how much SO3 we produced

16 g of O2 ( 1mol O2/ 32g )(8 mol SO3/ 15mol O2) =0.267 mol SO3

Then

0.267 mol SO3 (80gram / 1mol SO3)= 21.36 grams of SO3 is produced