Question

How many grams of sodium are needed to combine with 35.5 grams of chlorine to make 58.5 grams of sodium chloride

Answer 1

Hi,

Please find below the solution to the asked query:

Chemical Reaction:  2Na + Cl2 ----> 2NaCl

Moles of Na = 23 g / 23 g mol-1 = 1 mol

​From the above equation, for every 2 mole of Na we require 1 mole of Cl2​ , hence for 1 mole of Na we require = 1/2 mole of Cl2

​Mass of Cl2 required = (1/2) mol x 71 g mol-1 = 35.5 g

Hence, 23 g of Na with 35.5 g of Cl2 will give you 58.5 g of NaCl.



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Answer 2

we know that sum of reactants = sum of products

so,
sodium+chlorine = sodium chloride

sodium+35.5= 58.5

sodium=58.5-35.5

sodium = 23 g

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