Question

How many grams of solid NaH2PO4, and Na2HPO4, are required to prepare 1dm3 of 0.1 M phosphate buffer of pH=71 pk, is 6.8 for buffer. Atomic weight Na=23, P=31, O=16a) NaH,PO, = 4.00 gram, Na2HPO4 = 9.46 gramb) NaH,PO,= 9.46 gram, Na, HPO = 4.00 gram.c) Nah2PO4 = 0.4 gram, Na2HPO4 = 0.946 gramd) NaH2PO4= 0.946 gram, Na2 HPO4= 0.4 gram.​

Answer 1

Answer:

try from this below explanation

Explanation:

Sample CalculationTheoretical yield of product=12.641 g Na2S2O3x (1 mol 12.641 g Na2S2O3 / 126 g) x (1 mol Na2S2O3·5H2O / 1 mol Na2S2O3) = 0.1003254 mol Na2S2O3·5H2O0.1003254 mol Na2S2O3·5H2O x 248 g Na2S2O3·5H2O = 24.88 gPercentage yield= (10.391 g / 24.88 g) x 100 = 41.76%Discussion The theoretical yield of Na2S2O3· ...