How many grams of solid sodium hydroxide are required to make 175.00 mL of a 0.5100 M NaOH solution?
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- M=wt/Gmwt×1000/v
- 0.5100=wt/40×1000/175.00
- 0.5100=wt/40×5.714
- wt/40=0.0892
- wt=40×0.0892
- wt=3.5701g
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