How many grams of water are produced from 1.25 moles of methane?
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Work in moles. The molar mass of CH4 is 16g/mol. The molar mass of O2 is 32g/mol.
The equation for the combustion of methane is:
CH4 + 2O2 --> CO2 + 2H2O
Find the limiting reagent. you have 13.5/16 mols of methane and 40/32 mols of oxygen.
.84375 mol CH4
1.25 mol O2
For every mole of CH4 you need 2 mols of O2, according to our equation above. So for .84375 mol CH4, you would need twice as many, 1.6875, mol O2. You don't have that.
So all the O2 will be used up, and some methane will be left over.
1.25 mol O2 and .625 mol CH4. will be used, according to our equation and mol ratios, again.
The mol ratios for production are: for one mol of Oxygen consumed, one mol of water is formed. We established that 1.25 mol of O2 will be consumed, so 1.25 mol of H2O will be produced. The molar mass of water is 18 g/mol.
So 18g/mol * 1.25 mol gives you 22.5 g of H2O.(water)
The equation for the combustion of methane is:
CH4 + 2O2 --> CO2 + 2H2O
Find the limiting reagent. you have 13.5/16 mols of methane and 40/32 mols of oxygen.
.84375 mol CH4
1.25 mol O2
For every mole of CH4 you need 2 mols of O2, according to our equation above. So for .84375 mol CH4, you would need twice as many, 1.6875, mol O2. You don't have that.
So all the O2 will be used up, and some methane will be left over.
1.25 mol O2 and .625 mol CH4. will be used, according to our equation and mol ratios, again.
The mol ratios for production are: for one mol of Oxygen consumed, one mol of water is formed. We established that 1.25 mol of O2 will be consumed, so 1.25 mol of H2O will be produced. The molar mass of water is 18 g/mol.
So 18g/mol * 1.25 mol gives you 22.5 g of H2O.(water)
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