Question

How many grams of water is produced by the complete combustion of methane?

Answer 1

converting mass to number of moles:

16g of methane = 1 mole of CH4 as Molecular weight of CH4 is 16

(16 gram/ 16 gram per mole )

so, CH4 + 2O2 → CO2 +2H2O

16 gm + 2* (32 gm) → 80 gm of products (CONSERVATION OF MASS but not Moles)

of 80 gm, one mole of CO2 is equivalent to 44 gm ( as MW= 44 gm/mol)

S0, 80–44= 36 gm ( 2* 18 gm) of water.

Answer 2

Answer:

36 gram of water is produced by the complete combustion of methane.