Question

How many grams of water is required to dissolve 25grams of sodium sulphate to get 20% solution? *

Answer 1

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▪️Mass of the solution = mass of solute + mass of solvent

▪️Given that the mass percent of sodium sulphate solution is 20%.

▪️Let the mass of sodium sulphate which is required to prepare this solution be x grams.

▪️Given that the mass of water is 100 g.

▪️So,

▪️20 = [x/(x + 100)] * 100

▪️20/100 = [x/x + 100]

▪️1/5 = x/x + 100

▪️x + 100/5 = x

▪️x + 100 = 5x

▪️5x - x = 100

▪️4x = 100

▪️x = 100/4

▪️x = 25

▪️Thus, 25g of sodium sulphate is required.

Hopes it help you✌️✌️

Answer 2

Answer:

$\large{\bf{\blue{\underline{\underline{Hi....!! }}}}}$

▪️Mass of the solution = mass of solute + mass of solvent

▪️Given that the mass percent of sodium sulphate solution is 20%.

▪️Let the mass of sodium sulphate which is required to prepare this solution be x grams.

▪️Given that the mass of water is 100 g.

▪️So,

▪️20 = [x/(x + 100)] * 100

▪️20/100 = [x/x + 100]

▪️1/5 = x/x + 100

▪️x + 100/5 = x

▪️x + 100 = 5x

▪️5x - x = 100

▪️4x = 100

▪️x = 100/4

▪️x = 25

▪️Thus, 25g of sodium sulphate is required.