Question

How many grams of water should you add to 33.0 g of sucrose, to get a 0.795 m solution?

Answer 1

Explanation:

Molality =

$\frac{mass \: of \: sucrose \times 1000}{molar \: mass \: of \: sucrose \times mass \: of \: water}$

given, Molality = 0.795 m

Mass of sucrose = 33 g

Molar mass of sucrose = 342 g/mol

Mass of water = m

so,

$0.795 = \frac{33 \times 1000}{342 \times m}$

m = 121.37 g

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