Chemistry, asked by srushti2176, 9 months ago

how many grams of water will be produced by complete combustion of 12 gram of Methane Gas choose the correct option A 16 B 27 C 36d 56 ​

Answers

Answered by kobenhavn
84

Answer: B) 27 g

Explanation:

CH_4+2O_2\rightarrow CO_2+2H_2O

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of methane}=\frac{12g}{16g/mol}=0.75moles

According to stoichiometry :

1 mole of methane produces 2 moles of water

Thus 0.75 moles of methane produce=\frac{2}{1}\times 0.75=1.5moles moles of water

Mass of water= moles\times {\text {Molar Mass}}=1.5\times 18=27g

Thus mass of water produced by complete combustion of 12 gram of methane gas is 27 grams.

Answered by gauri21d
22

Answer:

27 grams is correct

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