Chemistry, asked by dipakratna4357, 10 months ago

How many grams of zinc are required to liberate 22.4l's of Hydrogen from sulphuric acid

Answers

Answered by stew123

1

H2SO4 + Zn = ZnSO4 + H2

22.4L of H2 means 1 mol of H2

I mol of Zn is required ie 65.3g

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