How many grams of zinc are there in 22.7 g of zncl2?
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Claculate the molecular mass of ZnCl2. take the mole mass of Zn and divide by that total. now you have percent composition of Zn. Multiply it by 22.7g and you are done.
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Answer:
10.93g
Explanation:35(Zn)*22.7/135(Zncl2)
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