How many grams of Zinc should be treated with excess of dil.HCl to obtain 2.24 litres of
H2 gas at STP? Calculate number of HCl molecules needed to produce 2.24 litres of
H2(g). (Atomic mass of zinc = 65)
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Answer:
0.65 gram
Explanation:
At STP 224 mL of hydrogen corresponds to
224/1000 × 22.4 = 0.01 moles of hydrogen.
They will be produced from the reaction of 0.01 mole of Zn with 0.01 mole of sulphuric acid. And thus , the mass of zinc required is 65.38×0.01=0.65 g.
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