Question

How many grams required to make 2.0 N Oxalic acid?​

Answer 1

n. factor for H
2
​
C
2
​
O
4
​
=2
Equivalent weight =
2
M
​

Normality =
equivalentweight×volume(inmL)
weight×1000
​

0.1=
(
2
126
​
)×250
weight×1000
​

Therefore, weight = 1.575g
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Answer 2

Answer:

126g of oxalic acid is required to make 1L of 2N oxalic acid solution.

Explanation:

Oxalic acid (H₂C₂O₄) is a dibasic acid as two acidic H⁺ present in the compound.

       So, n-factor = 2

molecular weight of H₂C₂O₄ = 126g/mol.

equivalent weight  is given by ,

      equivalent weight = molecular weight / n-factor

⇒    equivalent weight of H₂C₂O₄ = 126/2 =63g/eq.mol

Normality is given by,

           $normality = \frac{weight}{equivalent\; weight \times liters \;of \;solution}$

we have to make 2N oxalic acid. assuming the volume of solution prepared is 1L. then,

weight of H₂C₂O₄ = 2N × 63g/eq.mol. × 1L = 126g

Hence 126g of oxalic acid is required to make 1L of 2N oxalic acid solution.