How many grams water will be produced by complete compusion of 8 gram
methane gas?
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Answer:
Explanation:
To solve such questions you must write a balanced reaction first.
CH4 (g)+2O2 (g)————-> CO2 (g) +2H2O (g)
Now according to the reaction 1 mole of CH4 gives 2 moles of H2O
And 8 grams of Methane mean 1 mole (moles=given mass/molecular mass. Molecular mass of methane is 16)
so 1 mole of methane = 8/16 (given mass 8 and molecular mass 16)
since 1 mole of methane is getting used up to form 2 mole of water.
number of moles=given mass/molecular mass ——- eq. 1
molecular mass of water is 18.
2=x/18 ( where x is the mass of water produced , using equation 1)
2*18=36grams
so 36 grams of water will be produced.
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