Question

How many H atoms are present in 0.325 g of NH3​

Answer 1

Answer:

here is ur answer........

Answer 2

Answer:

In $0.325g$ of $NH_{3}$, the number of the H-atoms present is $4.56\times 10^{24}$ atoms.

Explanation:

Given,

The mass of $NH_{3}$ = $0.325g$

In $0.325g$ of $NH_{3}$, the number of the H-atoms present =?

As we know,

• The molar mass of $NH_{3}$ = $17g/mol$

Thus,

• The number of moles = $\frac{Given mass}{Molar mass}$ = $\frac{0.325}{17}$ = $0.019mol$

Now,

• $1$ mole = $6.022\times 10^{23}$ molecules
• $0.019$ moles = $0.019\times 6.022\times 10^{23}$ molecules = $0.114\times 10^{23}$ molecules

Also, in one molecule of $NH_{3}$ = $3$ H-atoms

Thus, $0.114\times 10^{23}$ molecules of $NH_{3}$ = $4\times 0.114\times10^{23}$ H-atoms = $4.56\times 10^{24}$ H-atoms.