How many hexadecimal digits are needed to define the netid?
Answers
Answered by
0
Answer:
Class B has 2 bytes (16 bits) netid and from the binary notation we see that Class B address starts with 10, so there are total 14 bits that can be changed out of 16.
Therefore total number of blocks in Class B = 214 = 16,384
There are 2 bytes (16 bits) for hostid in Class B so total number of host in each block = 216 = 65,536
So total number of addresses in Class B = No. of Blocks in Class B x No. of Hosts in each block of Class B
= 16,384 x 65,536
= 1,073,741,824
This is 25% of the total addresses in IPv4.
Explanation:
Similar questions