Question

How many hours does it take to reduce
3 mol of Fe+3 to Fe+2 with 2A of
current ? [R = 8.214 J/Kmol]​

Answer 1

Answer:

40.2hour

Explanation:

The electrode reaction is.

The reduction of 1 mol of Fe3+ to Fe2+ needs 1F electricity, therefore

For reduction of 3 mol of Fe3+ to Fe2+ needs 3x1F electricity

We know that 1F = 96,500 C/mol; given data current = 2 A

As per the equation,

t = charge/current

= 3 x 96,500/2

= 144750 seconds or 40.2 hours