Question

how many hydrogen atoms are present in 64u of methane

Answer 1

CH4=1 * 12 u+ 4 * 1u = 16 u
1CH4 = 16 u
64 u = 4* 16 u
4CH4 = 64 u
no.of h atoms are 4*4=16 atoms

Answer 2

16 atoms of Hydrogen are present in 64 u of methane.

Given:

Mass of Methane (CH₄) present = 64 u

To Find:

Number of Hydrogen atoms present in 64 u of Methane

Solution:

→ A molecule of methane contains one carbon atom and four hydrogen atoms. The structural geometry of the methane molecule is tetrahedral. It exhibits sp³ hybridization where the central carbon atom is surrounded by four hydrogen atoms present at the four corners. The bond length is about 109 pm and the angle between two hydrogen atoms in the arrangement is about 109.5°.

• Chemical Formula of Methane: CH₄

• Mass of one molecule of CH₄ = 16 u

Number of Hydrogen atoms present in 1 molecule of Methane = 4 atoms

∴ Number of Hydrogen atoms present in 16 u of Methane = 4 atoms

∴ Number of Hydrogen atoms in 64 u of Methane:

                                       $\frac{4}{16} (64)=\frac{1}{4}(64)=16$

∴ 16 atoms of Hydrogen are present in 64 u of Methane (CH₄).

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