how many hydrogen does 2NH3 contains?
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N2+3H2⇌2NH3. Starting with one mole of nitrogen and 3moles of hydrogen, at equilibrium 50% of each had reacted. If the equilibrium pressure is P, the partial pressure of hydrogen at equilibrium would be:
A .
P/2
B .
P/3
C .
P/4
D .
P/6
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Initial mole ratio N2:H2 is 1:3
At equilibrium, 50% of N2, H2 has reacted and equilibrium pressure is P
N2+3H2→2NH3y3y2y
At equilibrium, 50% of each reactant reacted, the number of moles will become half.
The mole of N2=y−2y
The moles of H2=3y−23y
THE moles of NH3=22y
Total moles at equilibrium=2y+23y+22y=3y
Partial pressure of H2=TotalmolesMolesofH2×Totalpressure=23y×3y1×
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Hey dear mate here is the correct answer.
this formula contain 6 hydrogen.
Hope it will help you..
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