Question

how many hydrogen ions are present in 1 ml of solution of PH 13​

Answer 1

In 1 ml of solution of pH 13, $6.022\times10^7$ hydrogen ions are present.

Given:

Volume of the solution = 1 ml

pH of the solution = 13

To find:

Number of hydrogen ion present = ?

Formula to be used:

Number of ions = $[H^+]$+ Volume in L + Avogadro number$(N_0)$

Calculation:

• From the pH of the solution, the  $[H^+]$ is identified as 13, which can be written as $10^{-13}$ .
• As volume must be in Liters, the given value in ml is converted into liters and it gives 1 ml = 0.001 L.
• The constant value for Avogadro number is $6.022\times 10^{23}$.
• Substituting the obtain values in the following formula gives the number of hydrogen ions:

Number of ions = $[H^+]$× Volume in L × Avogadro number$(N_0)$

Number of ions = $10^{-13}$ × 0.001 × ($6.022\times 10^{23}$)

Number of ions = $6.022\times 10^{23}\times10^{-16}$

Number of ions = $6.022\times 10^{7}$

Conclusion:

Thus it is inferred that 1 ml of solution with pH 13 has $6.022\times10^7$ hydrogen ions.

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Answer 2

Answer:

6.023×10*7

Explanation:

pH 13of 100ml solution contains 10*-3M[H+]

Im[H+]=6. 023×10*23ions

10*-13M[H+]=6. 023×10*10ions

1mlcontains "6. 023×10*7"ions