Question

How many images are formed if an object is placed between three mutually perpendicular plane mirrors?

Answer 1

Hey friend
here is your answer


$as \: the \: no. \: of \: images \: formed \: = \frac{360}{ \alpha } - 1\\ the \: no. \: of \: images \: formed \: = \frac{360}{90} - 1 \\ the \: no. \: of \: images \: formed \: = 4 - 1 = 3$
as there are three mirrors mutually perpendicular to each other, so no. of images formed = 9.


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Answer 2

Answer:

6

Explanation:

By regular methods we can deduce that the number of images that are supposed to form are 9 but we are forgetting about one key component, overlap of images.

If we were to draw the circles in which the images are supposed to form using the three mirrors, we would get that there are 3 intersecting points, meaning the images overlap on those 3 points. (so we get -3)

therefore answer is 9-3 = 6, notice that I haven't added an image as it is not clear whether the object is been placed at the center or anywhere between the space of mirrors.