Question

how many integers are between 200and 500 are diviaible by 8

Answer 1

a= 208. d=8 Tn=496 n=?

Tn= a+(n-1)d
496= 208+(n-1)8
288= 8n-8
8n = 296
n= 37

Answer 2

Let a be the first term and d be the common difference.

The first number between 200 and 500 divisible by 8 = 208.

Therefore a = 208.

The last number between 200 and 500 divisible by 8 = 496.

Therefore an = 496.

Common difference d = 8.


We know that sum of n terms of an AP an = a + (n - 1) * d

496 = 208 + (n - 1) * 8

496 = 208 + 8n - 8

496 = 200 + 8n

496 - 200 = 8n

296 = 8n

n = 296/8

n = 37.


Therefore the number of integers between 200 and 500 divisible by 8 = 37.


Hope this helps!