Question

How many integers between 100 and 999 consist of distinct even digits?

Answer 1

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All even integers between 100 and 999 are divisible by 2. So, there are 450 even integers between 100 and 999 and Hence 450 integers between 100 and 999 can be divided by 2.

Answer 2

There are 320 numbers between 100 and 999 consist of distinct even digits

Step-by-step explanation:

Given: The range of numbers between 100 and 999

To be found: Number of integers between the range

Solution:

Let us assume the three digits number as xyz.

Hundred's placing -x

Ten's place - y

One's place -z

The digits can be formed from 0 to 9 numbers.

The first digit x can be$1, 2, 3 , 4, 5 , 6 , 7 , 8 , 9$

Therefore, the digits has $8$ number of ways.

The second digit can be $0$ to $9$ and the numbers are not to be repeated.

Therefore, it has $8$ number of ways.

The third digit can be $0,2,4,6,8$

therefore, it has $5$ number of ways.

The total number of ways $=8$×$8$×$5$

=320 ways.

Hence, there are 320 number ways can be formed between 100 to 999