how many integers from 28 to 98, both exclusive are exactly divisible by 7 ?
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Answer:
0 since we know natural number are 123456etc.
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abhi569
In Arithmetic Progressions,
a = first term
d = common difference
a₂ = second term = a + d
aₓ = x th term
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Smallest number between 25 and 129 which is divisible by 7 is 28
Largest number between 25 and 129 which is divisible by 7 is 126
It means that 28 is the first term
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