How many integers n are there such that n+1 divides n2 +1
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n=1 because n must be a positive odd number and 2 is divisible by ( n+1).
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First note that n2 – 1 = (n + 1)(n – 1).
So, (n + 1)|n2 – 1 for all integer n except (–1).
Now, suppose (n+1)| (n2 + 1).
Therefore, n+1 | (n2 + 1) – (n2 – 1)=2
⇒ n+1 is a factor of 2.
So, possible values (n+1) can be 1, 2, (–1) or (–2).
Therefore, possible values of n are 0, 1, (–2) or (–3).
Verify that each of them satisfies the given condition.
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