How many integral zeroes does the polynomial 3z3 + 8z2 - 1 have?
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Answer:
3z3 + 8z2 - 1 =
Let f(z) = 3z³ + 8z² - 1
= The possible integral zeros of f(z) are -1 and 1
= f(-1) = 3(-1)³ + 8(-1)² - 1 ≠≠ 0
= -1 is not a zero of f(z)
= f(1) = 3(1)³ + 8(1)² - 1 ≠≠ 0
= ∴ f(z) has no integral zeros
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