How many ions are present in 7.45 g of potassium oxide?
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Answered by
5
Answer:
Number of moles of K2O in given sample = Total mass/molar mass
= 7.45/(39 + 39 + 16)
= 7.45/94
=> Number of molecules = Number of moles x Avogadro's Number
= (7.45/94) x N
=> Number of ions = Number of molecules x 3
= (7.45/94) x N x 3
Answered by
5
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SOLUTION⤵⤵
Number of moles of K2O in given sample = Total mass/molar mass
= 7.45/(39 + 39 + 16)
= 7.45/94
=> Number of molecules = Number of moles x Avogadro's Number
= (7.45/94) x N
=> Number of ions = Number of molecules x 3
= (7.45/94) x N x 3
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