Chemistry, asked by Sankalp0, 21 days ago

How many ions of calcium and nitride are present in 0.0592 g Calcium Nitride?

Answers

Answered by syedrehan46249
1

Answer:

n

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Correct option is C)

The overall cell reaction is given by:

Cu

2+

+H

2

→Cu+2H

+

E

cell

=E

Cu

2+

/Cu

−E

H

+

/H

2

⟹E

cell

=0.337−0=0.337V [standard hydrogen electrode potential is zero].

Now, E

cell

=0.337−

2

0.059

log[

[Cu

2+

]

[H

+

]

2

]

E

cell

=0.337−

2

0.059

log(

(0.1)

(0.01)

2

)

E

cell

=0.425V

Option C is correct.

Video Explanation

Answered by harinder172j
1

Answer:

Hope it's correct thank you ♥

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