Question

How many ions of sodium ion and chloride ion will be present in 30g of NaCl?

Answer 1

Answer:

na and cl ions are equal i.e. 0.20*NA = 1.2044*10^23 ions. Hope this is correct.

Answer 2

Answer:  2.990

×

10

^23  ions

Explanation:

14.5g of  N

a

C

l  is equal to 0.248 mol according to the equation  n

=

m

/M

Now, this equates to  1.495

×

10

^23  Sodium chloride molecules.

We get this if we multiply 0.248 mol with Avogadro's number,  6.022

×

10

^23

Each molecule of Sodium chloride holds two atomic ions bonded in an ionic bond-  N

a

+  and C

l

−  in a 1:1 ratio. This means that the amount of molecules correspond with each of the individual ions.

So :

Number of Sodium ions=Number of Chloride ions=  1.495

×

10

^23  ions

So the total amount of ions is twice this number,  2.990

×

10

^23  ions in total.

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