How many kg of solvent would contain 0.056 moles of KBr in a 7.3 molality solution?
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Answer:
it is very simple.
molality = no of moles/mass of solvent ( in kg)
mass of solvent =no of moles/molality
=0.056/ 7.3 = 0.00767 kg
≈7.6×10^-3 kg of solvent
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