How many kg of sulphur is needed if 108kg of aluminium is reacted to form 300kg of aluminium sulphide?
Answers
Answered by
0
Answer:
300- 108
=192g
Explanation:
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Answered by
3
Answer:
moles Al = 108 x 10^3 g/ 27 g/mol=4000
the ratio between Al and Al2S3 is 2 : 1
theoretical moles Al2S3 = 4000 x 1/2= 2000
actual moles Al2S3 = 300 x 10^3 g /150 g/mol=2000
the ratio between Al and S is 2 : 3
moles S needed = 4000 x 3 / 2 = 6000
mass S = 6000 mol x 32 g/mol=1.92 x 10^5 g => 192 Kg
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