How many kilograms of sweet worth rupee 110 per kg must be mixed with 30 kg of sweets of rupee 80 per kg to produce a mixture which costs rupee 100 per kg?
Answers
Answer:
The answer is 160 kg.
Step-by-step explanation:
Hi here is the step-by-step explanation :-
Let the sweet worth 110 rupees = x
Cost of the sweet worth 110 rupees = 110 x
Cost of the sweets worth rupees 80 per kg = 80 × 30 = 2,400
So, lets say 110 x + 2,400 = 100( x + 80)
= 110 x + 2,400 = 100 x + 800 (Using distributive property)
= 110 x - 100 x = +800 - 2,400 (We have transposed the values, and the symbols change while transposing from LHS to RHS or RHS to LHS)
= 10 x = 1,600 (We subtracted the values)
= x = 1,600/ 10 (We transposed the 10 to the LHS, so it will divide with 1,600)
= x = 160
Therefore, 160 kg worth of sweets should be mixed with sweets worth 80 per kg to form a mixture of 100 per kg.
Answer:
60 kg of ₹110 per kg
Step-by-step explanation:
sweet of 40 kg cost rupees 80 perkg
sweet of x kg cost rupees 110 per kg
from mixture of cost =₹100/kg
let,
x kg=amount of sweet is ₹100/kg(per kg)
:. total cost of sweet equals to
total cost of 30 kg swset=80×30
=2400
mixture weight = x+30
:. total cost of both sweets=total cost of mixture
110x+2400 = (x+30)100
110x+2400 =100x+3000
110x-100x =3000-2400
10x =600
x =600/10
x = 60
:. 60 kg of ₹110 per kg.