Question

how many kilograms of water must evaporate from a 60 kg woman to lower her body temperature by 0.750° C​

Answer 1

Answer:

For human body c=3470 J/kg.

At 37.0ºC the heat of vaporization Lv for water is 2430 kJ/kg or 580 kcal/kg

m•c•Δt= m(cond) •L(v)

m(cond) = m•c•Δt/L(v) =

=60•3470•0.75/2430000 =6.43•10⁻² kg=64.3 g