Question

How many liter of 30% alcohal solution and how many litres of 60% alcohol solution must be mixed to produce 18 liter of 50% solution​

Answer 1

Step-by-step explanation:

Let x = liters of 30% alcohol

and y = liters of 60% alcohol

.

Then, since we have two unknowns we need two equations:

x + y = 18 (equation 1)

.30x + .60y = .50(x+y) (equation 2)

.

Solve equation 1 for y:

x + y = 18

y = 18-x

.

Substitute the above into equation 2 and solve for x:

.30x + .60y = .50(x+y)

.30x + .60(18-x) = .50(x+18-x)

.30x + 10.8 - .60x = .50(18)

10.8 - .30x = 9

-.30x = -1.8

x = 6 liters (of 30% alcohol)

.

Substitute the above into equation 1 and solve for y:

x + y = 18

6 + y = 18

y = 12 liters (of 60% alcohol)

Answer 2

Answer:

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The answer 12 Liter